1800 United States presidential election in Rhode Island

The 1800 United States presidential election in Rhode Island took place as part of the 1800 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.

1800 United States presidential election in Rhode Island

← 1796 October 31 - December 3, 1800 1804 →

Nominee John Adams Thomas Jefferson Party Federalist Democratic-Republican Home state Massachusetts Virginia Electoral vote 4 0 Popular vote 2,353 2,159 Percentage 52.15% 47.85%   Nominee Charles C. Pinckney John Jay Party Federalist Federalist Home state South Carolina New York Electoral vote 3 1

County Results Adams   50-60%   60-70%   70-80% Jefferson   50-60%   60-70%

President before election John Adams Federalist Elected President Thomas Jefferson Democratic-Republican

Rhode Island voted for the Federalist candidate, John Adams, over the Democratic-Republican candidate, Thomas Jefferson. Adams won Rhode Island by a margin of 4.3%. All 4 Adams electors received more votes than the 4 Jefferson electors and the electoral vote was all for Adams in Rhode Island.