1804 United States presidential election in Ohio

The 1804 United States presidential election in Ohio took place as part of the 1804 United States presidential election. Voters chose three representatives, or electors, to vote for president and vice president. It was the first time that Ohio took part in United States presidential election.

1804 United States presidential election in Ohio

1808 →
 
NomineeThomas JeffersonCharles C. Pinckney
PartyDemocratic-RepublicanFederalist
Home stateVirginiaSouth Carolina
Running mateGeorge ClintonRufus King
Electoral vote30
Popular vote2,593364
Percentage87.69%12.31%

President before election

Thomas Jefferson
Democratic-Republican

Elected President

Thomas Jefferson
Democratic-Republican

Results

edit
1804 United States presidential election in Ohio[1]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanThomas Jefferson (incumbent)2,59387.69%3
FederalistCharles Cotesworth Pinckney36412.31%0
Totals2,957100.0%3

References

edit
  1. ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 3, 2023.