1958 Wimbledon Championships – Boys' singles

Jimmy Tattersall was the defending champion, but lost to Premjit Lall in the semifinals.

Boys' singles
1958 Wimbledon Championships
Final
ChampionUnited States Butch Buchholz
Runner-upIndia Premjit Lall
Score6–1, 6–3
Events
Singlesmenwomenboysgirls
Doublesmenwomenmixedboysgirls
← 1957 ·Wimbledon Championships· 1959 →

Butch Buchholz defeated Lall in the final, 6–1, 6–3 to win the boys' singles tennis title at the 1958 Wimbledon Championships.[1]

Draw

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Finals

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SemifinalsFinal
          
Butch Buchholz686
Ronnie Barnes863
Butch Buchholz66
Premjit Lall13
Premjit Lall66
Jimmy Tattersall22

Top half

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First roundSecond roundQuarterfinalsSemifinals
Butch Buchholz66
Lassie Lincoln41
E Buchholz66
J Leschly31
Karim Fawaz32
Jan Leschly66
E Buchholz686
R Barnes863
Guiliano Fanfani01
Ronnie Barnes66 R Barnes66
A Ahmad00 R Barnes714
A Abreu636 A Potanin512
C Coste364 A Abreu10
Alain Bresson36 A Potanin66
Andrei Potanin68

Bottom half

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First roundSecond roundQuarterfinalsSemifinals
José Luis Arilla66
Srdjan Jelić00 JL Arilla376
Thomas Hallberg66 T Hallberg652
Bernard Auberson11 JL Arilla45
TE Vold13 P Lall67
Michael Hickey66 M Hickey01
Premjit Lall66
P Lall66
J Tattersall22
Piotr Jamroz76
Jan Beukers53
P Jamroz624
J Tattersall266
Peter Pokorny05
Jimmy Tattersall67

References

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  1. ^ "Boys' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
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